How do you graph y>=log_6 x?

1 Answer
Nov 20, 2016

Graph is inserted. The region including the graph and above is the answer. See explanation

Explanation:

Use log_b a = log a/log b.

y=log x/log 6, x > 0, to make log x real

The graph cuts x-axis at (0, 1).

As x to 0, y to -oo.

As x to oo, y to oo.

For any (x, y) on or above the graph, y>=log_6x

graph{log x/log 6 [-2.5, 2.5, -1.25, 1.25]}