How do you identify the vertex for the graph of y=−3x2+6x−4?
1 Answer
May 4, 2017
Explanation:
for the standard quadratic function y=ax2+bx+c
the x-coordinate of the vertex xvertex=−b2a
for y=−3x2+6x−4
a=−3,b=6 and c=−4
⇒xvertex=−6−6=1
substitute this value into function and evaluate for y
yvertex=−3(1)2+6(1)−4=−1
⇒vertex =(1,−1)
graph{-3x^2+6x-4 [-10, 10, -5, 5]}
