How do you implicitly differentiate #x+sqrty=7#?

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Answer 1 · 2018-07-27T15:24:07

#dy/dx=2x-14#

Given equation:

#x+\sqrty=7#

differentiating above equation w.r..t #x# on both the sides as follows

#d/dx(x+\sqrty)=d/dx(7)#

#d/dx(x)+d/dx\sqrty=0#

#1+1/{2\sqrty}dy/dx=0#

#dy/dx=-2\sqrty#

#dy/dx=-2(7-x)#

#dy/dx=2x-14#

Answer 2 · 2018-07-27T18:57:07

# dy/dx=-2(7-x)#.

# x+sqrty=7#.

# :. sqrty=7-x#.

# :. y=(7-x)^2#.

#:. dy/dx=2(7-x)*d/dx(7-x)=-2(7-x)#.