How do you integrate $(1/(16+x^2))$ ?

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Answer 1 · 2016-09-01T19:13:44

$int 1/(16+x^2)dx=1/4arc tan (x/4)+C$ .

We know that $int1/(a^2+x^2)dx=1/aarc tan(x/2)+C$ .

$:. int 1/(16+x^2)dx=1/4arc tan (x/4)+C$ .

How do you integrate (1/(16+x^2))(1/(16+x^2))?