Question

How do you integrate `(1/(16+x^2))`?

Answer 1

`int 1/(16+x^2)dx=1/4arc tan (x/4)+C`.

Explanation:

We know that `int1/(a^2+x^2)dx=1/aarc tan(x/2)+C`.

`:. int 1/(16+x^2)dx=1/4arc tan (x/4)+C`.