How do you integrate $1/x^2$ ?

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Answer 1 · 2016-07-09T15:56:47

$int1/(x^2)dx=-1/x+C$

This function can be written as $x^-2$ .

To integrate such function we can use the general formula:

$int x^alpha=x^(alpha+1)/(alpha+1)$ for any rational $alpha$

Using this formula we get:

$int1/(x^2)dx=intx^(-2)dx=x^-1/(-1)+C=-1/x+C$

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