How do you integrate $[1/(x^2-4)] dx$ ?

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Answer 1 · 2016-07-18T04:29:24

$int (1/(x^2-4)) dx=1/4*ln ((x-2)/(x+2))+C$

Use the formula

$int dx/(u^2-a^2)=1/(2a)*ln ((u-a)/(u+a))+C$

God bless....I hope the explanation is useful.

How do you integrate [1/(x^2-4)] dx [1/(x^2-4)] dx?