How do you integrate $(2x)/(x²-1)$ ?

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Answer 1 · 2016-05-28T11:04:21

$int (2x)/(x^2-1) d x=l n(x^2-1)+C$

$int (2x)/(x^2-1) d x=?$

$x^2-1=u$

$2x d x=d u$

$int (2x)/(x^2-1) d x=int (d u)/u=l n u +C$

$int (2x)/(x^2-1) d x=l n(x^2-1)+C$

How do you integrate (2x)/(x²-1) (2x)/(x²-1) ?