How do you integrate $(\frac{5}{\sqrt{x}}) d x$ $(5/sqrt x) dx$ ?

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Answer 1 · 2016-08-04T21:39:07

$\int \frac{5}{\sqrt{x}} d x = 10 \sqrt{x} + C$ $int 5/(sqrt(x))d x=10 sqrt x +C$

$\int \frac{5}{\sqrt{x}} d x = ?$ $int 5/(sqrt(x))d x=?$

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$\int 5 {(x)}^{- \frac{1}{2}} d x = 5 \int {(x)}^{- \frac{1}{2}} d x$ $int 5(x)^(-1/2)d x=5 int(x)^(-1/2) d x$

$\int \int \frac{5}{\sqrt{x}} d x = 5 (\frac{1}{- \frac{1}{2} + 1}) x^{- \frac{1}{2} + 1}$ $int int 5/(sqrt(x))d x=5(1/(-1/2+1)) x^(-1/2+1)$

$\int \frac{5}{\sqrt{x}} d x = 5 \cdot 2 \cdot x^{\frac{1}{2}}$ $int 5/(sqrt(x))d x=5*2*x^(1/2)$

$\int \frac{5}{\sqrt{x}} d x = 10 \sqrt{x} + C$ $int 5/(sqrt(x))d x=10 sqrt x +C$

How do you integrate (5√x)dx(5/sqrt x) dx?