How do you integrate $(x-2)/(x-1)$ ?

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Answer 1 · 2016-06-23T09:06:25

$x - ln(x-1) + C$

$(x-2)/(x-1) = (x-1-1)/(x-1) = 1 - (1)/(x-1)$

$int \ 1 - (1)/(x-1) \ dx = x - ln(x-1) + C$

How do you integrate (x-2)/(x-1)(x-2)/(x-1)?