How do you integrate $((x^3 + 7) / x^2) dx$ ?

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Answer 1 · 2016-11-30T19:19:56

$int((x^3+7)/x^2)dx= frac (x^3-14) (2x)$

$int((x^3+7)/x^2)dx = int (x^3/x^2+7/x^2)dx = int xdx+7int x^(-2)dx$

$= x^2/2-7x^-1 = x^2/2-7/x = frac (x^3-14) (2x)$

How do you integrate ((x^3 + 7) / x^2) dx((x^3 + 7) / x^2) dx?