How do you integrate $x/(x+1)dx$ ?

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Answer 1 · 2016-07-29T17:04:28

$int x/(x+1) dx = x-ln abs(x+1)+C$

$int x/(x+1) dx$

$=int (x+1-1)/(x+1) dx$

$=int (1-1/(x+1)) dx$

$= x-ln abs(x+1)+C$

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