How do you multiply #1/2^3#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer anor277 Sep 15, 2016 Well it's simply #1/(2xx2xx2)# #=# #1/8# Explanation: And thus #1/2^0=1/1=1#, And #1/2^1=1/2#, #1/2^2=1/4# And, #1/2^3=1/8#. Capisce? Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1314 views around the world You can reuse this answer Creative Commons License