How do you multiply $- 2 x^{3} (3 x^{2} + 4 x + 5)$ $-2x^3(3x^2+4x+5)$ ?

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How do you multiply $- 2 x^{3} (3 x^{2} + 4 x + 5)$ $-2x^3(3x^2+4x+5)$ ?

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Answer 1 · 2018-03-23T16:26:26

$- 6 x^{5} - 8 x^{4} - 10 x^{3}$ $-6x^5-8x^4-10x^3$

Explanation:

$- 2 x^{3} (3 x^{2}) = - 6 x^{5}$ $-2x^3(3x^2)=-6x^5$
$- 2 x^{3} (4 x) = - 8 x^{4}$ $-2x^3(4x)=-8x^4$
$- 2 x^{3} (5) = - 10 x^{3}$ $-2x^3(5)=-10x^3$
Combine:
$- 6 x^{5} - 8 x^{4} - 10 x^{3}$ $-6x^5-8x^4-10x^3$

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How do you multiply $- 2 x^{3} (3 x^{2} + 4 x + 5)$ $-2x^3(3x^2+4x+5)$ ?

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How do you multiply -2x^3(3x^2+4x+5)−2x3(3x2+4x+5)-2x^3(3x^2+4x+5)?

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How do you multiply $- 2 x^{3} (3 x^{2} + 4 x + 5)$ $-2x^3(3x^2+4x+5)$ ?