How do you multiply $(3m+1)(m-4)(m+5)$ ?

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Answer 1 · 2014-11-12T23:54:26

$(3m+1)(m-4)(m+5)$

by distributing $(m-4)$ to $3m$ and $1$ ,

$=[3m(m-4)+1(m-4)] (m+5)$

by distributing $3m$ ,

$=(3m^2-12m+m-4)(m+5)$

by collecting like terms,

$=(3m^2-11m-4)(m+5)$

by distributing $(m+5)$ ,

$=3m^2(m+5)-11m(m+5)-4(m+5)$

by distributing $3m^2$ , $-11m$ , and $-4$ ,

$=3m^3+15m^2-11m^2-55m-4m-20$

by collecting like terms,

$=3m^3+4m^2-59m-20$

I hope that this was helpful.

How do you multiply (3m+1)(m-4)(m+5)(3m+1)(m-4)(m+5)?