Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you multiply $(- 3 t^{2} + 4 t - 7) (- 2 t)$ $(-3t^2+4t-7)(-2t)$ ?

1 Answer

Jun 25, 2015

$(- 3 t^{2} + 4 t - 7) (- 2 t)$ $(-3t^2+4t-7)(-2t)$
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ $= 6 t^{3} - 8 t^{2} + 14 t$ $=6t^3-8t^2+14t$

Explanation:

The Distributive Property (of Multiplication over Addition) tells us:
$XXXX$ $color(white)("XXXX")$ $(a + b + c) \times (d) = a d + b d + c d$ $(a+b+c) xx (d) = ad +bd+cd$

So $(- 3 t^{2} + 4 t - 7) (- 2 t)$ $(-3t^2+4t-7)(-2t)$
$XXXX$ $color(white)("XXXX")$ $= (- 3 t^{2}) \cdot (- 2 t) + (4 t) \cdot (- 2 t) - (7) \cdot (- 2 t)$ $= (-3t^2)*(-2t)+(4t)*(-2t)-(7)*(-2t)$

$XXXX$ $color(white)("XXXX")$ $= 6 t^{3} - 8 t^{2} + 14 t$ $=6t^3-8t^2+14t$

Related questions

See all questions in Multiplication of Monomials by Polynomials

Impact of this question

1660 views around the world

You can reuse this answer
Creative Commons License