How do you multiply $4 x^{2} y (- x^{2} - x + 10)$ $4x^2y(-x^2-x+10)$ ?

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How do you multiply $4 x^{2} y (- x^{2} - x + 10)$ $4x^2y(-x^2-x+10)$ ?

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Answer 1 · 2017-02-09T19:29:57

$- 4 x^{4} y - 4 x^{3} y + 40 x^{2} y$ $-4x^4y-4x^3y+40x^2y$

Explanation:

Multiply each term in the bracket by $4 x^{2} y$ $4x^2y$

$\Rightarrow 4 x^{2} y (- x^{2} - x + 10)$ $rArrcolor(red)(4x^2y)(-x^2-x+10)$

$= (4 x^{2} y \times - x^{2}) + (4 x^{2} y \times - x) + (4 x^{2} y \times 10)$ $=(color(red)(4x^2y)xx-x^2)+(color(red)(4x^2y)xx-x)+(color(red)(4x^2yxx10))$

$= - 4 x^{4} y + (- 4 x^{3} y) + 40 x^{2} y$ $=-4x^4y+(-4x^3y)+40x^2y$

$= - 4 x^{4} y - 4 x^{3} y + 40 x^{2} y$ $=-4x^4y-4x^3y+40x^2y$

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How do you multiply $4 x^{2} y (- x^{2} - x + 10)$ $4x^2y(-x^2-x+10)$ ?

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How do you multiply $4 x^{2} y (- x^{2} - x + 10)$ $4x^2y(-x^2-x+10)$ ?