How do you multiply $(x^{2} + 8 x + 2) (7 x + 6)$ $(x ^ { 2} + 8x + 2) ( 7x + 6)$ ?

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How do you multiply $(x^{2} + 8 x + 2) (7 x + 6)$ $(x ^ { 2} + 8x + 2) ( 7x + 6)$ ?

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Answer 1 · 2018-06-18T10:15:14

$\Rightarrow 7 x^{3} + 62 x^{2} + 62 x + 12$ $color(blue)(=> 7x^3 + 62x^2 + 62x + 12$

Explanation:

$(x^{2} + 8 x + 2) 897 x + 6)$ $(x^2 + 8x + 2) 8 97x + 6)$

$\Rightarrow x^{2} \cdot 7 x + 8 x \cdot 7 x + 2 \cdot 7 x + x^{2} \cdot 6 + 8 x \cdot 6 + 2 \cdot 6$ $=> x^2 * 7x + 8x * 7x + 2 * 7x + x^2 * 6 + 8x * 6 + 2 * 6$

$\Rightarrow 7 x^{3} + 56 x^{2} + 14 x + 6 x^{2} + 48 x + 12$ $=> 7x^3 + 56x^2 + 14x + 6x^2 + 48x + 12$

$\Rightarrow 7 x^{3} + 62 x^{2} + 62 x + 12$ $color(blue)(=> 7x^3 + 62x^2 + 62x + 12$

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How do you multiply $(x^{2} + 8 x + 2) (7 x + 6)$ $(x ^ { 2} + 8x + 2) ( 7x + 6)$ ?

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Explanation:

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How do you multiply (x ^ { 2} + 8x + 2) ( 7x + 6)(x2+8x+2)(7x+6)(x ^ { 2} + 8x + 2) ( 7x + 6)?

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How do you multiply $(x^{2} + 8 x + 2) (7 x + 6)$ $(x ^ { 2} + 8x + 2) ( 7x + 6)$ ?