How do you prove # 1 / (1-sin^2 x) =1+tan^2 x#? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer sankarankalyanam Mar 21, 2018 As proved below. Explanation: #L H S = 1 / (1 - sin^2 x)# #=> 1 / cos^2 x #, #"using identity " cos^2x + sin^2x = 1# #=> sec^2 x #, as # cos x = 1 / sec x# #=> 1 + tan^2 x# # "using identity " 1 + tan^2x = sec^2x# #hence = R H S# Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove #\csc \theta \times \tan \theta = \sec \theta#? How do you prove #(1-\cos^2 x)(1+\cot^2 x) = 1#? How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#? How do you prove that #cos 2x(1 + tan 2x) = 1#? How do you prove that #(2sinx)/[secx(cos4x-sin4x)]=tan2x#? How do you verify the identity: #-cotx =(sin3x+sinx)/(cos3x-cosx)#? How do you prove that #(tanx+cosx)/(1+sinx)=secx#? How do you prove the identity #(sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)#? See all questions in Proving Identities Impact of this question 13429 views around the world You can reuse this answer Creative Commons License