How do you prove (cosx/(1+sinx))+((1+sinx)/cosx)=2secx? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer Alan P. ยท John D. Jul 23, 2015 Convert the left side into terms with common denominator and add (converting cos^2+sin^2 to 1 along the way); simplify and refer to definition of sec = 1/cos Explanation: (cos(x)/(1+sin(x)))+((1+sin(x))/cos(x)) = (cos^2(x) + 1+2sin(x) + sin^2(x))/(cos(x)( 1+sin(x) = (2 +2sin(x))/(cos(x)(1+sin(x)) = 2/cos(x) = 2* 1/cos(x) = 2sec(x) Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove \csc \theta \times \tan \theta = \sec \theta? How do you prove (1-\cos^2 x)(1+\cot^2 x) = 1? How do you show that 2 \sin x \cos x = \sin 2x? is true for (5pi)/6? How do you prove that sec xcot x = csc x? How do you prove that cos 2x(1 + tan 2x) = 1? How do you prove that (2sinx)/[secx(cos4x-sin4x)]=tan2x? How do you verify the identity: -cotx =(sin3x+sinx)/(cos3x-cosx)? How do you prove that (tanx+cosx)/(1+sinx)=secx? How do you prove the identity (sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)? See all questions in Proving Identities Impact of this question 83518 views around the world You can reuse this answer Creative Commons License