How do you prove $(cos x) (csc x) (tan x) = 1$ $(cosx)(cscx)(tanx)=1$ ?

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Answer 1 · 2016-05-15T15:09:03

$(cos x) (csc x) (tan x) = 1$ $(cosx)(cscx)(tanx)=1$

$(cos x) (\frac{1}{sin x}) (\frac{sin x}{cos x}) = 1$ $(cosx)(1/sinx)(sinx/cosx)=1$

I multiply $cos x$ $cosx$ by $(\frac{sin x}{sin x})$ $(sinx/sinx)$

$(\frac{cos sin x}{sin x}) (\frac{1}{sin x}) (\frac{sin x}{cos x}) = 1$ $(cossinx/sinx)(1/sinx)(sinx/cosx)=1$

$\frac{cos x}{cos x} = 1$ $cosx/cosx=1$

I use
http://www.regentsprep.org/regents/math/algtrig/ATT9/morepythag.htm
to assist me in proving trigonometric identities and equations.
In the end, you have to play around with it.

How do you prove(cosx)(cscx)(tanx)=1 (cosx)(cscx)(tanx)=1?