How do you prove cosX / (secX - tanX) = 1 + sinX? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer sankarankalyanam Mar 11, 2018 As below. Explanation: To prove cos x / (sec x - tan x) = (1 + sin x) L H S = cos x / ((1/cos x) - (sin x / cos x) as color(blue)(sec x = 1/cos x, tan x = sin x / cos x => cos x / ((1 - sin x) / cos x) as color(green)(cos x is the L C M of Denominator. => cos^2 x / (1 - sin x) => = (1 - sin^2 x) / (1 - sin x) as color(blue)(cos^2x = 1 - sin^2x => ((1+ sin x) *color(red)(cancel (1 - sin x))) /color(red)(cancel (1 - sin x)) => 1 + sin x Q E D Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove \csc \theta \times \tan \theta = \sec \theta? How do you prove (1-\cos^2 x)(1+\cot^2 x) = 1? How do you show that 2 \sin x \cos x = \sin 2x? is true for (5pi)/6? How do you prove that sec xcot x = csc x? How do you prove that cos 2x(1 + tan 2x) = 1? How do you prove that (2sinx)/[secx(cos4x-sin4x)]=tan2x? How do you verify the identity: -cotx =(sin3x+sinx)/(cos3x-cosx)? How do you prove that (tanx+cosx)/(1+sinx)=secx? How do you prove the identity (sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)? See all questions in Proving Identities Impact of this question 26006 views around the world You can reuse this answer Creative Commons License