Question

How do you prove `(sec^2 x-1)/sec^2x=sin^2x`?

Answer 1

see below

Explanation:

Left Side: `=(sec^2x-1)/sec^2x`

`=sec^2x/sec^2x -1/sec^2x`

`=1-cos^2x`

`=sin^2x`

`=`Right Side