How do you prove #(sin^3x + cos^3x)/sin^3x = cscx/(1-cosx)#? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer sente Jan 22, 2016 The equality is not correct. Explanation: Let #x = pi/6#: #(sin^3(pi/6) + cos^3(pi/6))/sin^3(pi/6) = (1/8+(3sqrt(3))/8)/(1/8) = 1+3sqrt(3)# #csc(pi/6)/(1-cos(pi/6)) = 2/(1-sqrt(3)/2) = 8+4sqrt(3)# Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove #\csc \theta \times \tan \theta = \sec \theta#? How do you prove #(1-\cos^2 x)(1+\cot^2 x) = 1#? How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#? How do you prove that #cos 2x(1 + tan 2x) = 1#? How do you prove that #(2sinx)/[secx(cos4x-sin4x)]=tan2x#? How do you verify the identity: #-cotx =(sin3x+sinx)/(cos3x-cosx)#? How do you prove that #(tanx+cosx)/(1+sinx)=secx#? How do you prove the identity #(sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)#? See all questions in Proving Identities Impact of this question 1244 views around the world You can reuse this answer Creative Commons License