How do you prove $sin 2 x = (tan x) (1 + cos 2 x)$ $sin2x=(tanx)(1+cos2x)$ ?

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How do you prove $sin 2 x = (tan x) (1 + cos 2 x)$ $sin2x=(tanx)(1+cos2x)$ ?

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Answer 1 · 2016-05-13T04:04:22

Prove trig expression

Explanation:

Use the trig identities:
sin 2x = 2sin x.cos x
$1 + cos 2 x = 2 {cos}^{2} x$ $1 + cos 2x = 2cos^2 x$
Right side of the equation -->
$(\frac{sin x}{cos x}) (2 {cos}^{2} x) = 2 sin x . cos x = sin 2 x$ $((sin x)/(cos x))(2cos^2 x) = 2sin x.cos x = sin 2x$ . OK

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How do you prove $sin 2 x = (tan x) (1 + cos 2 x)$ $sin2x=(tanx)(1+cos2x)$ ?

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Explanation:

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How do you prove sin2x=(tanx)(1+cos2x)sin2x=(tanx)(1+cos2x)?

1 Answer

Explanation:

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How do you prove $sin 2 x = (tan x) (1 + cos 2 x)$ $sin2x=(tanx)(1+cos2x)$ ?