How do you simplify $(tan^2 (theta) csc^2 (theta)-1) / tan^2(theta)$ ?

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Answer 1 · 2016-07-16T06:01:35

1

$(tan^2 theta csc^2 (theta)-1) / tan^2theta$

$=(cancel(sin^2theta)/cos^2theta* 1/cancel(sin^2 theta)-1) / tan^2theta$

$=(1/cos^2theta-1) / tan^2theta$

$=(sec^2theta-1) / tan^2theta$

$=tan^2theta / tan^2theta=1$

How do you simplify (tan^2 (theta) csc^2 (theta)-1) / tan^2(theta)(tan^2 (theta) csc^2 (theta)-1) / tan^2(theta)?