How do you prove #tan(-A)=-tanA#?

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Answer 1 · 2016-11-17T21:35:50

see below

#tan(-A)=-tanA#

Use the even and odd property. That is, #cos(-x)=cosx# and #sin(-x)=-sinx#

Left Side:#=tan(-A)#

#=sin(-A)/cos(-A)#

#=(-sinA)/cosA#

#=-sinA/cosA#

#=-tanA#

#:.=#Right Side