How do you prove $(tany+coty)/cscy=secy$ ?

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Answer 1 · 2016-09-18T05:18:28

Please see below.

$(tany+coty)/cscy$

= $(siny/cosy+cosy/siny)xx1/(1/siny)$

= $(sinyxxsiny+cosyxxcosy)/(sinycosy)xxsiny$

= $(sin^2y+cos^2y)/(cancelsinycosy)xxcancelsiny$

= $1/cosy$

= $secy$

How do you prove (tany+coty)/cscy=secy(tany+coty)/cscy=secy?