How do you prove this ? sum_(n=1)^oo a_n converges -> sum_(n=1)^oo a_n^2 converges
1 Answer
Jun 5, 2017
The assertion is false.
Explanation:
The assertion is false.
For example:
sum_(n=1)^oo (-1)^n/sqrt(n)" " converges
sum_(n=1)^oo 1/n" " diverges