How do you put #2x-3y=6# in slope intercept form?

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Answer 1 · 2018-07-26T22:53:38

#y=2/3x-2#

#y=mx+b#, with slope #m# and #y#-intercept of #b#.

We essentially just want a #y# on the left side, so let's subtract 2x# from both sides to get

#-3y=-2x+6#

Lastly, let's divide both sides by #-3# to get

#y=2/3x-2#

Our equation is now in slope-intercept form, where the slope is #2/3# and our #y#-intercept is #-2#.

Hope this helps!