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How do you put y=2(x+1)^2-32 into factored form?

1 Answer

Oct 7, 2016

$y = 2 (x + 3) (x - 1) .$ $y=2(x+3)(x-1).$

Explanation:

$y = 2 {(x + 1)}^{2} - 32$ $y=2(x+1)^2-32$

$= 2 {{(x + 1)}^{2} - 16}$ $=2{(x+1)^2-16}$

$= 2 {{(x + 1)}^{2} - 4^{2}}$ $=2{(x+1)^2-4^2}$

$=2{(x+1)+2}{(x+1)-2}......[a^2-b^2=(a+b)(a-b)]$

$:. y=2(x+3)(x-1).$

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