How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#?

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Answer 1 · 2018-06-15T09:42:37

as below.

Case : 1 #"If the given sum is "(2x) / (sqrt5 x)#

#"Then ",(2x * sqrt5) / (sqrt5 x * sqrt5)#

#=> (2sqrt5 cancelx) /( 5 cancelx) = color(maroon)((2 sqrt5) / 5#

Case : 2 #"If the given sum is " (2x) / sqrt(5x)#

#"Then " => (2x * sqrt(5x)) / (sqrt(5x) * sqrt(5x))#

#=> (2 sqrt5 * cancelx sqrtx) / (5 cancelx)#

#=> color(maroon)(2 sqrt(5x)) / 5#