How do you simplify #7/(""^3sqrt(5)#?

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How do you simplify #7/(""^3sqrt(5)#?

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Answer 1 · 2018-05-09T14:32:22

#=(7*"3rd root"25)/5#

Explanation:

#7/("3rd root"5)# Multiply be #1/1# as #("3rd root"25)/("3rd root"25)#
#=(7*"3rd root"25)/("3rd root"125)#
#=(7*"3rd root"25)/5#
Sorry, I don't know how to use 3rd root symbols.

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How do you simplify #7/(""^3sqrt(5)#?

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