How do you simplify $1/(b^-7xxb^5)$ ?

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Answer 1 · 2015-09-25T18:20:32

The answer is $b^2$ .

When multiplying variables with exponents, add the exponents.

$x^m*x^n=x^(m+n)$

$1/(b^(-7)xxb^5)=$

$1/(b^(-7+5))=$

$1/(b^(-2))$

Apply exponent rule $x^(-a)=1/x^a$

$b^(-2)=1/b^2$

$1/(1/(b^2)$

Invert and multiply.

$cancel1xxb^2/cancel1=b^2$

How do you simplify 1/(b^-7xxb^5)1/(b^-7xxb^5)?