How do you simplify (14x^2y^2z^2)/(21xy^8z^4)? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan P. Jun 15, 2015 (14x^2y^2z^2)/(21xy^8z^4)= x/(7y^6z^2) Explanation: (14x^2y^2z^2)/(21xy^8z^4) can be grouped as similar components: color(white)("XXXX")=(14/21) * ((x^2)/(x)) * ((y^2)/(y^8)) * ((z^2)/(z^4)) color(white)("XXXX")= 1/7 * x/1 * 1/(y^6) * 1/(z^2) color(white)("XXXX")= x/(7y^6z^2) Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression (2^2/3^3)^3? How do you simplify the expression \frac{a^5b^4}{a^3b^2}? How do you simplify ((a^3b^4)/(a^2b))^3 using the exponential properties? How do you simplify \frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}? Which exponential property do you use first to simplify \frac{(2a^2bc^2)(6abc^3)}{4ab^2c}? How do you simplify (x^5y^8)/(x^4y^2)? How do you simplify [(2^3 *-3^2) / (2^4 * 3^-2)]^2? See all questions in Exponential Properties Involving Quotients Impact of this question 1892 views around the world You can reuse this answer Creative Commons License