How do you simplify (-16a^5b^3)/(-24a^5b^7)? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Don't Memorise Jun 18, 2015 = color(blue)(2/3b^(-4) Explanation: (-16a^5b^3)/(-24a^5b^7) = ((-cancel16)/-cancel24) . (cancel(a^5/a^5)) . (b^3/b^7) = (2/3) . color(blue)(b^3/b^7 Note: color(blue)(a^m/a^n= a^(m-n) Applying the above to the exponents of b = (2/3) color(blue)(b^(3-7) = 2/3 color(blue)(b^(-4) Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression (2^2/3^3)^3? How do you simplify the expression \frac{a^5b^4}{a^3b^2}? How do you simplify ((a^3b^4)/(a^2b))^3 using the exponential properties? How do you simplify \frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}? Which exponential property do you use first to simplify \frac{(2a^2bc^2)(6abc^3)}{4ab^2c}? How do you simplify (x^5y^8)/(x^4y^2)? How do you simplify [(2^3 *-3^2) / (2^4 * 3^-2)]^2? See all questions in Exponential Properties Involving Quotients Impact of this question 1595 views around the world You can reuse this answer Creative Commons License