How do you simplify $(-18x^-2y^2x^4y^3) /(6x^5y^6)$ ?

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Answer 1 · 2015-06-07T17:19:23

You can simplify numbers with numbers and similar letters in accordance to their exponents;

Remember few rules of exponents:
1) $x^a/x^b=x^(a-b)$
2) $x^-a=1/x^a$
3) $x^a*x^b=x^(a+b)$

In your case:

$(-18/6)((x^-2*x^4)/x^5)((y^2*y^3)/y^6)=$
$=-3(x^(-2+4-5))(y^(2+3-6))$
$=-3x^-3y^-1=-3/(x^3y)$

How do you simplify (-18x^-2y^2x^4y^3) /(6x^5y^6)(-18x^-2y^2x^4y^3) /(6x^5y^6)?