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How do you simplify $\frac{24 x y^{2}}{- 48 x^{3} y}$ $(24xy^2)/ (-48x^ 3 y)$ ?

1 Answer

May 7, 2015

$f (x) = \frac{24 . x . y^{2}}{- 48 . x^{3} y} = - \frac{y}{2 . x^{2}}$ $f(x) = (24.x.y^2)/(-48.x^3 y) = -y/(2.x^2)$

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