How do you simplify $(25a^4 + 19a^2 - a - 78)/(5a^2 + 6a - 9)$ ?

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Answer 1 · 2018-05-31T12:27:49

It is $((5a-6)(5a^3+6a^2+11a+13))/(5a^2+6a-9)$

Expanding

$(5a-6)(5a^3+6a^2+11a+13)$

we get

$25a^4+19a^2-a-78$

How do you simplify (25a^4 + 19a^2 - a - 78)/(5a^2 + 6a - 9)(25a^4 + 19a^2 - a - 78)/(5a^2 + 6a - 9)?