How do you simplify (2a^-2)/(2a)^-3?

1 Answer
Mar 12, 2017

See the entire solution process below:

Explanation:

First, use these rules for exponents to simplify the denominator:

a = a^color(red)(1) and (x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))

(2a^-2)/((2a)^-3) = (2a^-2)/((2^color(red)(1)a^color(red)(1))^color(blue)(-3)) = (2a^-2)/((2^(color(red)(1)xxcolor(blue)(-3))a^(color(red)(1)xxcolor(blue)(-3)))) = (2a^-2)/(2^-3a^-3)

We can now use these three rules for exponents to complete the simplification:

a = a^color(red)(1) and a^color(red)(1) = a and x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))

(2a^-2)/(2^-3a^-3) = (2^color(red)(1)a^color(red)(-2))/(2^color(blue)(-3)a^color(blue)(-3)) = 2^(color(red)(1)-color(blue)(-3))a^(color(red)(-2)-color(blue)(-3)) = 2^(color(red)(1)+color(blue)(3))a^(color(red)(-2)+color(blue)(3) =

2^4a^1 = 16a