How do you simplify $\frac{2 b^{2} - a b}{a - 2 b}$ $(2b^2-ab)/(a-2b)$ ?

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Answer 1 · 2016-11-10T16:34:59

Factor.

$\Rightarrow \frac{b (2 b - a)}{a - 2 b}$ $=>(b(2b - a))/(a - 2b)$

$\Rightarrow \frac{- b (a - 2 b)}{a - 2 b}$ $=>(-b(a - 2b))/(a - 2b)$

$\Rightarrow - b$ $=> -b$

Our restrictions are that $a - 2 b \neq 0$ $a - 2b !=0$ .

Hopefully this helps!

How do you simplify (2b^2-ab)/(a-2b)2b2−aba−2b(2b^2-ab)/(a-2b)?