How do you simplify $(-2r^(-4))^(2)(-3r^(2)2^(8))^(-1)$ ?

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Answer 1 · 2018-05-07T12:37:46

$-1/(172 r^10)$

There are two laws of indices which we can use to start.

#(xyz)^color(blue)(m) = x^color(blue)(m)y^color(blue)(m)z^color(blue)(m)" and " x^color(red)(-m) = 1/x^color(red)

$(-2r^(-4))^color(blue)(2)(-3r^(2)2^(8))^color(red)(-1)$

$=(-2)^2r^(-8) xx 1/(-3r^(2)2^(8))^color(red)(1)$

$=4/color(teal)(r^8) xx 1/(-3color(teal)(r^2) 2^8)" " larr color(teal)(x^m xx x^n = x^(m+n))$

$= - cancel4^1/(3color(teal)(r^10) cancel256_64)$

$=-1/(172 r^10)$

How do you simplify (-2r^(-4))^(2)(-3r^(2)2^(8))^(-1) (-2r^(-4))^(2)(-3r^(2)2^(8))^(-1) ?