How do you simplify $((2s^-1t^3)/(6s^2t^-4))^-3$ ?

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Answer 1 · 2016-09-05T04:45:54

Start by getting rid of the exponent on the outside.

$=((6s^2t^-4)/(2s^-1t^3))^3$

Use the quotient rule $(a^n/a^m = a^(n - m))$ and division to simplify further.

$=(3s^3t^-7)^3$

Use the power rule $(a^n)^m = a^(n xx m)$ to simplify.

$=27s^9t^-21$

$=(27s^9)/(t^21)$

Hopefully this helps!

How do you simplify ((2s^-1t^3)/(6s^2t^-4))^-3((2s^-1t^3)/(6s^2t^-4))^-3?