How do you simplify $\frac{- 2 w^{3}}{w (w^{2} + 4)}$ $(-2w^3)/( w(w^2 + 4))$ ?

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Answer 1 · 2015-05-31T18:43:33

$- 2 w^{3}$ $-2w^3$ = $w(-2w²)$

You can thus take out the w's

$=(-2w²)/(w²+4)$

How do you simplify (-2w^3)/( w(w^2 + 4))−2w3w(w2+4)(-2w^3)/( w(w^2 + 4))?