How do you simplify $(2x^2-8)/(4x-8)$ ?

Question

2358 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-01T12:37:49

$(2x^2-8)/(4x-8)$ = $(2(x^2-4))/(4(x-2))$

$= (2(x^2-2^2))/(4(x-2))$

We know that $color(blue)(a^2 - b^2 = (a+b)(a-b)$

$=(2(x+2)cancel((x-2))) / (4cancel((x-2))$

$= (2(x+2))/4$

$=color(green)((x+2)/2$

How do you simplify (2x^2-8)/(4x-8)(2x^2-8)/(4x-8)?