How do you simplify $\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}}$ $(2x^-6)/(7y^-3)^-3$ using only positive exponents?

Question

How do you simplify $\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}}$ $(2x^-6)/(7y^-3)^-3$ using only positive exponents?

1 Answer

Impact of this question

1364 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-27T04:29:40

$\frac{686}{x^{6} y^{9}}$ $686/(x^6y^9)$

Explanation:

Given: $\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}}$ $(2x^-6)/(7y^-3)^-3$

Use the exponent rules $x^{- n} = \frac{1}{x^{n}} and \frac{1}{x^{- m}} = x^{m}$ $x^-n = 1/x^n " and " 1/x^-m = x^m$

And the exponent power rule ${(x^{m} y^{n})}^{c} = x^{m \cdot c} y^{n \cdot c}$ $(x^m y^n)^c = x^(m*c) y^(n*c)$

$\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}} = \frac{2}{x^{6} (7^{- 3} y^{9})} = \frac{2 \cdot 7^{3}}{x^{6} y^{9}} = \frac{2 \cdot 343}{x^{6} y^{9}} = \frac{686}{x^{6} y^{9}}$ $(2x^-6)/(7y^-3)^-3 = 2/(x^6(7^-3 y^9)) = (2*7^3)/(x^6y^9) = (2*343)/(x^6y^9) = 686/(x^6y^9)$

Science

Math

Humanities

... and beyond

How do you simplify $\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}}$ $(2x^-6)/(7y^-3)^-3$ using only positive exponents?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify 2x−6(7y−3)−3(2x^-6)/(7y^-3)^-3 using only positive exponents?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify $\frac{2 x^{- 6}}{{(7 y^{- 3})}^{- 3}}$ $(2x^-6)/(7y^-3)^-3$ using only positive exponents?