How do you simplify $\frac{2 x {(x + 6)}^{4} - x^{2} (4) {(x + 6)}^{3}}{{(x + 6)}^{8}}$ $[2x(x+6)^4-x^2(4)(x+6)^3]/(x+6)^8$ ?

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Answer 1 · 2017-07-02T02:19:58

Expression $= \frac{- 2 x (x - 6)}{{(x + 6)}^{5}}$ $= (-2x(x-6))/(x+6)^5$
$x \neq - 6$ $x!=-6$

Expression $= \frac{2 x {(x + 6)}^{4} - x^{2} (4) {(x + 6)}^{3}}{{(x + 6)}^{8}}$ $=(2x(x+6)^4-x^2(4)(x+6)^3)/(x+6)^8$

$= \frac{2 x {(x + 6)}^{4} - 4 x^{2} {(x + 6)}^{3}}{{(x + 6)}^{8}}$ $=(2x(x+6)^4-4x^2(x+6)^3)/(x+6)^8$

$= \frac{2 x {(x + 6)}^{3} \cdot (x + 6 - 2 x)}{{(x + 6)}^{8}}$ $=(2x(x+6)^3*(x+6-2x))/(x+6)^8$

$= \frac{2 x {(x + 6)}^{3} \cdot (- x + 6)}{{(x + 6)}^{8}}$ $=(2x(x+6)^3*(-x+6))/(x+6)^8$

$= \frac{- 2 x {(x + 6)}^{3} \cdot (x - 6)}{{(x + 6)}^{8}}$ $=(-2x(x+6)^3*(x-6))/(x+6)^8$

$=(-2xcancel((x+6)^3)*(x-6))/(x+6)^(8-3)$ [ $x!=-6$ ]

$=(-2x(x-6))/(x+6)^5$

How do you simplify [2x(x+6)^4-x^2(4)(x+6)^3]/(x+6)^82x(x+6)4−x2(4)(x+6)3(x+6)8[2x(x+6)^4-x^2(4)(x+6)^3]/(x+6)^8?