How do you simplify (2y^2-4y)/(16y)2y24y16y?

1 Answer
Jun 1, 2017

frac(y - 2)(8)y28; y ne 0y0

Explanation:

We have: frac(2 y^(2) - 4 y)(16 y)2y24y16y

Let's factorise the numerator:

= frac(2 y (y - 2))(16 y)=2y(y2)16y

Simplifying:

= frac(y - 2)(8)=y28

In the original fraction, the denominator is 16 y16y.

To prevent division by zero, this denominator cannot be equal to zero:

Rightarrow 16 y ne 016y0

Rightarrow y ne 0y0

therefore frac(y - 2)(8); y ne 0