How do you simplify $\frac{36 m^{4} n^{3}}{24 m^{2} n^{5}}$ $(36 m^4 n^3)/(24 m^2 n^5)$ ?

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Answer 1 · 2015-10-02T09:24:28

$= \frac{3}{2} m^{2} n^{- 2}$ $=color(blue)(3/2 m^color(blue)(2) n^color(blue)(-2)$

$\frac{36 m^{4} n^{3}}{24 m^{2} n^{5}}$ $(36m^4n^3)/(24m^2n^5)$

$= (cancel36/cancel24) * (m^4n^3)/(m^2n^5)$

$=(3/2) (m^4n^3)/(m^2n^5)$

As per properties:
$color(blue)(1/a=a^-1$

$color(blue)(a^m*a^n=a^(m+n)$

Applying the above properties to $m$ and $n$

$=(3/2) m^4n^3 * m^color(blue)(-2)n^color(blue)(-5)$

$=(3/2) * m^color(blue)((4-2)) n^color(blue)((3-5))$

$=(3/2) * m^color(blue)((2)) n^color(blue)((-2))$

$=color(blue)(3/2 m^color(blue)(2) n^color(blue)(-2)$

How do you simplify (36 m^4 n^3)/(24 m^2 n^5)36m4n324m2n5(36 m^4 n^3)/(24 m^2 n^5)?