How do you simplify $(39t^4uv^-2)/(13t^-3u^7)$ ?

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Answer 1 · 2017-05-23T07:17:05

Follow explanation. $(13*t^7)/(v^2*u^6)$

39 is 3 times larger than 13.

$39/13=3$

Now the alphabetic terms can be written as

$(t^4*t^3*u)/(v^2*u*u^6)$

When you simplify the above terms:

$t^7/(v^2*u^6)$ is obtained

Therefore your final answer is

$(13*t^7)/(v^2*u^6)$

This is your answer $(13*t^7)/(v^2*u^6)$

How do you simplify (39t^4uv^-2)/(13t^-3u^7)(39t^4uv^-2)/(13t^-3u^7)?