How do you simplify #((3f^4gh^4)/(32f^3g^4h))^0#?
1 Answer
Dec 24, 2016
Explanation:
Using the
#color(blue)"law of exponents"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^0=1)color(white)(2/2)|)))# The 'contents' of the bracket are all raised to the power of 0
#rArr((3f^4gh^4)/(32f^3g^4h))^0=1#
